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Routines |
| Prev: 28807 | Up: Map | Next: 28960 |
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| 28882 | LD L,110 | Bytes 109 and 110 of the character's buffer hold the address of the next character in the submessage | ||||||
| 28884 | LD A,(HL) | |||||||
| 28885 | AND A | Are we in a submessage at the moment? | ||||||
| 28886 | JR Z,28904 | Jump if not | ||||||
| 28888 | LD D,A | DE=address of the next character in the submessage | ||||||
| 28889 | DEC L | |||||||
| 28890 | LD E,(HL) | |||||||
| 28891 | LD A,(DE) | Pick up this character in A | ||||||
| 28892 | AND A | Has the submessage finished? | ||||||
| 28893 | JR Z,28901 | Jump if so | ||||||
| 28895 | NOP | |||||||
| 28896 | INC DE | Move to the next character in the submessage, and store its address in bytes 109 and 110 of the character's buffer | ||||||
| 28897 | LD (HL),E | |||||||
| 28898 | INC L | |||||||
| 28899 | LD (HL),D | |||||||
| 28900 | RET | |||||||
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The submessage has finished.
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| 28901 | LD (HL),A | Zero out bytes 109 and 110 of the character's buffer to indicate that the submessage is finished | ||||||
| 28902 | INC L | |||||||
| 28903 | LD (HL),A | |||||||
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We are dealing with the main message.
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| 28904 | LD L,108 | DE=address of the next character in the main message (collected from bytes 107 and 108 of the character's buffer) | ||||||
| 28906 | LD D,(HL) | |||||||
| 28907 | DEC L | |||||||
| 28908 | LD E,(HL) | |||||||
| 28909 | LD A,(DE) | Pick up the next character of the message | ||||||
| 28910 | INC DE | Move to the next character in the main message, and store its address in bytes 107 and 108 of the character's buffer | ||||||
| 28911 | LD (HL),E | |||||||
| 28912 | INC L | |||||||
| 28913 | LD (HL),D | |||||||
| 28914 | INC L | L=109 | ||||||
| 28915 | BIT 7,A | Is the ASCII code of the next character < 128? | ||||||
| 28917 | JR Z,28938 | Jump if so | ||||||
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The ASCII code of the next character is >= 128, which refers to an entry in one of the symbol/element, capital city/country and date/battle question-and-answer pairs.
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| 28919 | AND 127 | Set DE to 57088+12*(A-128) | ||||||
| 28921 | LD E,A | |||||||
| 28922 | EX DE,HL | |||||||
| 28923 | ADD A,A | |||||||
| 28924 | ADD A,L | |||||||
| 28925 | LD L,A | |||||||
| 28926 | LD H,56 | |||||||
| 28928 | JR NC,28931 | |||||||
| 28930 | INC H | |||||||
| 28931 | ADD HL,HL | |||||||
| 28932 | ADD HL,HL | |||||||
| 28933 | DEC H | |||||||
| 28934 | EX DE,HL | |||||||
| 28935 | LD A,(DE) | Pick up the first character of this submessage in A and store the next address in bytes 109 and 110 of the character's buffer | ||||||
| 28936 | JR 28896 | |||||||
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The ASCII code of the next character in the message is < 128.
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| 28938 | CP 32 | Return if the next character is a normal, printable character (ASCII code >= 32) | ||||||
| 28940 | RET NC | |||||||
| 28941 | CP 16 | Return if the ASCII code of the next character in the message is < 16 | ||||||
| 28943 | RET C | |||||||
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The ASCII code of the next character in the message is 16-24. We have a submessage to deal with, which will be one of the following:
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| 28944 | SUB 16 | Point DE at the appropriate submessage from the table above | ||||||
| 28946 | LD E,A | |||||||
| 28947 | ADD A,A | |||||||
| 28948 | ADD A,A | |||||||
| 28949 | ADD A,A | |||||||
| 28950 | SUB E | |||||||
| 28951 | ADD A,A | |||||||
| 28952 | ADD A,128 | |||||||
| 28954 | LD E,A | |||||||
| 28955 | LD D,217 | |||||||
| 28957 | LD A,(DE) | Pick up the first character of the submessage in A | ||||||
| 28958 | JR 28896 | Store the address of the next character in the submessage | ||||||
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